IBM Midrange Storage Technical Support V4 : C4090-461 exam

C4090-461 real exams

Exam Code: C4090-461

Exam Name: IBM Midrange Storage Technical Support V4

Updated: Sep 07, 2026

Q & A: 64 Questions and Answers

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IBM C4090-461 Exam Syllabus Topics:

SectionObjectives
Installation and Configuration- System setup procedures
  • 1. Initial system configuration
    • 2. Storage pool creation and configuration
      - Host attachment and mapping
      • 1. LUN provisioning
        • 2. Host zoning and masking
          Troubleshooting and Maintenance- Problem determination
          • 1. Log analysis and diagnostics
            • 2. Hardware failure isolation
              - System maintenance
              • 1. Preventive maintenance procedures
                • 2. Firmware upgrades
                  Administration and Management- Storage management tasks
                  • 1. Performance monitoring
                    • 2. Capacity management
                      - Data services
                      • 1. Replication concepts
                        • 2. Snapshots and cloning
                          IBM Storage Systems Fundamentals- Midrange storage architecture concepts
                          • 1. Storage system components overview
                            • 2. Controller and disk subsystem operations
                              - Storage connectivity
                              • 1. Fibre Channel fundamentals
                                • 2. iSCSI and SAN integration concepts

                                  IBM Midrange Storage Technical Support V4 Sample Questions:

                                  Question #1

                                  Which resource provides the complete support matrix for a specific IBM storage system?

                                  • A. SSIC
                                  • B. COMP
                                  • C. SSCT
                                  • D. PSAT
                                  Answer: A
                                  Question #2

                                  Which type of data benefits the least from data compression?

                                  • A. Databases
                                  • B. Media files
                                  • C. Vmware virtual machine files
                                  • D. Backup pools
                                  Answer: D
                                  Question #3

                                  A customer has a mission-critical application that requires the highest performance while providing redundancy.
                                  Which RAID configuration should be utilized?

                                  • A. RAID 10
                                  • B. RAID 5
                                  • C. RAID 6
                                  • D. RAID 0
                                  Answer: A
                                  Question #4

                                  A customer has conducted an analysis of its Vmware environment to determine the capacity savings available by converting from thick to thin provisioning. The results of the analysis are in the exhibit provided.

                                  What is the minimum capacity needed for the solution assuming compression is NOT part of the proposed solution?

                                  • A. 51540 GB
                                  • B. 17774 GB
                                  • C. 27060 GB
                                  • D. 33796 GB
                                  Answer: B
                                  Question #5

                                  A customer provides the information shown in the exhibit for the company's primary database environment. Solution requirements include meeting of exceeding the current I/O rate of the existing environment.
                                  System name Name Max IOPS Avg IOPS Min IOPS Max BW (MBps) Avg BW (MBps) Min BW (MBps) Max Latency (ms) Avg Latency (ms) pldenxivg3 denoubivs_arch1 1101 20 0 274 5 0 3 2 pldenxivg3 denoubivs_arch2 3 0 0 0 0 0 0 0 pldenxivg3 denoubivs_bin1 322 1 0 1 0 0 32 0 pldenxivg3 denoubivs_bin2 184 0 0 1 0 0 21 0 pldenxivg3 denoubivs_bkup1 2 0 0 0 0 0 0 0 pldenxivg3 denoubivs_bkup2 25 0 0 2 0 0 0 0 pldenxivg3 denoubivs_bkup3 1 0 0 0 0 0 0 0 pldenxivg3 denoubivs_data1 997 39 0 128 3 0 28 2 pldenxivg3 denoubivs_data2 997 38 0 133 3 0 31 2 pldenxivg3 denoubivs_data3 1005 43 0 127 3 0 23 1 pldenxivg3 denoubivs_data4 2217 38 0 175 3 0 19 2 pldenxivg3 denoubivs_data5 1194 37 0 109 2 0 32 1 pldenxivg3 denoubivs_data6 1118 30 0 70 2 0 23 1 pldenxivg3 denoubivs_data7 1111 29 0 70 2 0 21 1 pldenxivg3 denoubivs_data8 2443 24 0 156 1 0 10 0 pldenxivg3 denoubivs_data9 1710 8 0 108 0 0 12 1 pldenxivg3 denoubivs_log1 2107 49 0 46 1 0 2 0 pldenxivg3 denoubivs_log2 2174 44 0 43 1 0 2 0 pldenxivg3 denoubivs_NJP_bin 8 0 0 0 0 0 0 0 pldenxivg3 denoubivs_NJP_data 1452 9 0 93 0 0 0 0 pldenxivg3 denoubivs_NJP_log 65 14 0 3 0 0 0 0 pldenxivg3 denoubivs_os1 16 0 0 0 0 0 0 0 pldenxivg3 denoubivs_os2 0 0 0 0 0 0 0 0 pldenxivg3 denoubivs_pg1 12 0 0 1 0 0 0 0 pldenxivg3 denoubivs_pg2 0 0 0 0 0 0 0 0 pldenxivg3 denoubivs_arch1 501 5 0 122 1 0 3 1 pldenxivg3 denoubivs_arch2 0 0 0 0 0 0 0 0 pldenxivg3 denoubivs_back1 1 0 0 0 0 0 0 0 pldenxivg3 denoubivs_back2 0 0 0 0 0 0 0 0 pldenxivg3 denoubivs_back3 2 0 0 0 0 0 0 0 pldenxivg3 denoubivs_bin1 209 2 0 6 0 0 16 0 pldenxivg3 denoubivs_bin2 283 0 0 17 0 0 18 1 pldenxivg3 denoubivs_bin3 176 1 0 8 0 0 18 1 pldenxivg3 denoubivs_data1 3128 116 0 201 5 0 17 0 pldenxivg3 denoubivs_data2 1117 65 0 71 2 0 16 0 pldenxivg3 denoubivs_data3 1129 69 0 71 2 0 16 0 pldenxivg3 denoubivs_data4 1136 63 0 72 2 0 16 0 pldenxivg3 denoubivs_data5 1147 65 0 72 2 0 16 0 pldenxivg3 denoubivs_data6 3470 60 0 223 2 0 36 0 pldenxivg3 denoubivs_data7 2389 51 0 152 2 0 20 0 pldenxivg3 denoubivs_log1 204 12 0 13 0 0 2 0 pldenxivg3 denoubivs_log2 279 11 0 12 0 0 3 0 pldenxivg3 denoubivs_os1 21 0 0 0 0 0 0 0 pldenxivg3 denoubivs_os2 0 0 0 0 0 0 0 0 pldenxivg3 denoubivs_pg1 2 0 0 0 0 0 0 0
                                  Total= 35458 943 0 2580 44
                                  Average= 788 21 0 57 1 0 10
                                  0
                                  What should the minimum I/O rate be for the new solution?

                                  • A. 943 I/Os per second
                                  • B. 21 I/Os per second
                                  • C. 788 I/Os per second
                                  • D. 35458 I/Os per second
                                  Answer: B

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